遇到的問(wèn)題如下：第二個(gè)數(shù)碼管不亮，電平跳變都是對(duì)的。

如果在中斷的P1，P2賦值那一塊加上死循環(huán)兩個(gè)數(shù)碼管就都能亮了，

但是不能時(shí)刻測(cè)電壓值了，糾結(jié)。

道編程如下：

#include

unsigned char tab[16] = {

0xc0,0xf9,0xa4,0xb0,0x99,0x92,0x82,0xf8,

0x80,0x90,0x88,0x83,0xc6,0xa1,0x86,0x8e};

unsigned char xdata *ADC;

unsigned char num, s, g, sum;

void delay(unsigned int Delay)

{

unsigned int i;

for(;Delay;Delay--) for(i=0;i<54;i++);

}

void main()

{

IT0 = 1; EX0 = 1; EA = 1;

ADC = 0xf8fb;

*ADC = 0;

while(1) {

P2 = 0x02; P1 = tab[s]; delay(1); P2 = 0xf9;

P2 = 0x04; P1 = tab[g]; delay(1); P2 = 0xf9;

}

}

void A() interrupt 0

{

num = *ADC;

s = num / 16;

g = num % 16;

*ADC = 0;

}

試試看。